Find a whole number such that when one of its digit is erased, the resulting number is equal to one-ninth of the original number. The resulting number is also a multiple of 9.
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Answered by
11
90
If units digit is removed left over number is 9
Which is 1/9 th of 90
And 90/9=10
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3
Given,
The following hints are given -
when one of its digits is erased, the resulting number is equal to one-ninth of the original number
the resulting number is also a multiple of 9.
To find,
The whole number
Solution,
We have been given in one of the hints that if "one digit is erased", which means a required number is a two-digit number
Also, we know that the number is a multiple of 9, so it has to be a part of the table of 9
So, using the trial and error method, we get the number 90 where
If the units digit is removed remaining number is 9
Which is 1/9th of 90
And 90/9 = 10
So, it fills all the three criteria given
Thus, The whole number is 90
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