Find a2-b2 if a-b=.9 and ab=.36
Answers
Answered by
15
HEYA !
Given that,
a - b = 9 and ab = 36
We know the formula
(a + b)² = (a - b)² + 4ab
On putting given values , We get
(a + b)² = 9² + 4×(36)
→ (a + b)² = 81 + 144
→ (a + b)² = 225
→ (a + b) = ±15
Now,
★ When
a - b = 9 and a + b = 15
→ a² - b² = (a + b) (a - b)
→ a² - b² = 15 × 9
→ a² - b² = 135
★ When
a - b = 9 and a + b = -15
→ a² - b² = (a + b) (a - b)
→ a² - b² = -15 × 9
→ a² - b² = -135
HENCE,
a² - b² = 135 or -135
Given that,
a - b = 9 and ab = 36
We know the formula
(a + b)² = (a - b)² + 4ab
On putting given values , We get
(a + b)² = 9² + 4×(36)
→ (a + b)² = 81 + 144
→ (a + b)² = 225
→ (a + b) = ±15
Now,
★ When
a - b = 9 and a + b = 15
→ a² - b² = (a + b) (a - b)
→ a² - b² = 15 × 9
→ a² - b² = 135
★ When
a - b = 9 and a + b = -15
→ a² - b² = (a + b) (a - b)
→ a² - b² = -15 × 9
→ a² - b² = -135
HENCE,
a² - b² = 135 or -135
Answered by
8
Heya !!!
A- B = 9 ---------(1)
AB = 36 ----------(2)
From equation (1) we get,
A - B = 9
A = 9 + B -----------(3)
Putting the value of A in equation (2)
A × B = 36
(9 + B) × B = 36
B² + 9B -36 = 0
B² +12B -3B -36 = 0
B(B+12) -3(B+12) = 0
(B+12) (B-3) = 0
(B+12) = 0 OR (B-3) = 0
B = -12 or B = 3
Putting B = 3 in equation (3)
A = 9 + B
A = 9 +3 = 12
Therefore,
(A²-B²) = (A + B) ( A - B) => (A)² - (B)²
=> (12)² - (3)²
=> 144 - 9
=> 135
HENCE,
(A²-B²) = 135
HOPE IT WILL HELP YOU....... :-)
A- B = 9 ---------(1)
AB = 36 ----------(2)
From equation (1) we get,
A - B = 9
A = 9 + B -----------(3)
Putting the value of A in equation (2)
A × B = 36
(9 + B) × B = 36
B² + 9B -36 = 0
B² +12B -3B -36 = 0
B(B+12) -3(B+12) = 0
(B+12) (B-3) = 0
(B+12) = 0 OR (B-3) = 0
B = -12 or B = 3
Putting B = 3 in equation (3)
A = 9 + B
A = 9 +3 = 12
Therefore,
(A²-B²) = (A + B) ( A - B) => (A)² - (B)²
=> (12)² - (3)²
=> 144 - 9
=> 135
HENCE,
(A²-B²) = 135
HOPE IT WILL HELP YOU....... :-)
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