Find a³-b³ if a-b=6 and ab=20
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Hi mate
Here is ur answer ⬇️⬇️⬇️⬇️
a^3 - b^3 = (a-b) ( a^2 + b^2 + ab)
= (6)(a^2 + b^2 + 20)
= (6)[( a-b)^2 +2ab + 20]
{ (a-b)^2 = a^2+ b^2 - 2ab}
= (6)[(6)^2 + 2(20) + 20]
=( 6) [36+40+20]
=(6)(96)
= 576
I hope this will help you....
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