Joseph’s weight is two times the weight of his younger brother. Find Joseph’s weight if sum of their weights is 63 kg
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Answered by
88
Let weight of Joseph's younger brother = x Kg
Joseph's weight = 2x kg
A/C to question,
Joseph's weight + weight of Joseph's younger brother = 63 Kg
=> 2x + x = 63 Kg
=> 3x = 63
=> x = 21 Kg
hence, weight of Joseph's younger brother = 21kg
and Joseph's weight = 2 × 21 = 42 Kg
Joseph's weight = 2x kg
A/C to question,
Joseph's weight + weight of Joseph's younger brother = 63 Kg
=> 2x + x = 63 Kg
=> 3x = 63
=> x = 21 Kg
hence, weight of Joseph's younger brother = 21kg
and Joseph's weight = 2 × 21 = 42 Kg
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