Question

find a40+a50 if -1,2,5,8........are in AP​

Answer 1

Step-by-step explanation:

AP :- -1 , 2 , 5 , 8 , ..........

since, a1 = - 1

a2 = 2

therefore, d = a2 - a1

d = 2 - (-1)

d = 2 + 1

d = 3.

hence, a40 = a1 + 39d

= -1 + 39 × 3

= -1 + 117

a40 = 116

and,. a50 = a1 + 49d

= -1 + 49 × 3

= -1 + 147

a50 = 146.

Answer 2

Answer:

if the answer is wrong plz inform me