find acceleration due to gravity at certain height and at certain depth.
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Consider a test mass (m) taken to a distance (d) below the earth's surface, the acceleration due to gravity that point (gd) is obtained by taking the value of g in terms of density. When the depth d = 0, the value of g on the surface of the earth gd = g.
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➙ Consider a test mass (m) taken to a distance (d) below the earth’s surface, the acceleration due to gravity that point (gd) is obtained by taking the value of g in terms of density.
On the surface of the earth, the value of g is given by;
g = 4/3 × πρRG.
At a distance (d) below the earth’s surface, the acceleration due to gravity is given by;
gd = 4/3 × πρ × (R – d) G.
On dividing the above equations we get,
gd = g (R – d)/R.
When the depth d = 0, the value of g on the surface of the earth gd = g.
When the depth d = R, the value of g at the centre of the earth gd = 0.
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