Question

find acceleration of each block and friction between the blocks​

Answer 1

Answer- The above question is from the chapter 'Laws of Motion'.

Given question: Find acceleration of each block and friction between the blocks​.

(Diagram has been attached in the question itself.)

Answer: It is given that

m₁ = 10 Kg

m₂ = 5 Kg

$\mu_{s}$ = 0.5

$\mu_{k}$ = 0.4

F = 100 N

g = 10 m/s²

Let's check the condition.

μ(m₁ + m₂)g = 0.5 × (10 + 5) × 10 = 5 × 15 = 45 N

F = 100 N

100 > 45

Now, friction will be kinetic and bodies will move with different accelerations.

Let 10 Kg block move with a₁ and 5 Kg with a₂.

So, a₂ = μg = 0.4 × 10 = 4 m/s²

a₁ = $\frac{F \: - \: \mu m_{2} g}{m_{1}}$

a₁ = $\frac{100 \: - \: 0.4 \times 5 \times 10}{10}$

a₁ = $\frac{100 - 20}{10}$

a₁ = $\frac{80}{10}$

a₁ = 8 m/s²

Friction ($f_{k}$) = μm₂g = 0.4 × 5 × 10 = 20 N

∴ Acceleration of 10 Kg block = 8 m/s²

Acceleration of 5 Kg block = 4 m/s²

Friction between the blocks = 20 N

Answer 2

Answer:

Explanation:

acceleration of the system = 100/15 = 20/3 m/sec^2

static frictional force = 25 n

frictional force acting on blocks = 100/3

you can see it is more than static ones so blocks will slide over each other

so kinetic frictional force is applied

kinetic friction = 20 n

acceleration of 10kg block = 8m/sec^2

acceleration of 5 kg block = 4m/sec^2

frictional force between them = 20n