Find accumulated charges
capacitors in the given circuit.
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Va = Vb = 20 Volts
As capacitors are in series connection, the accumulated charges in both the capacitors will be of same value..
From the equation, q = C.V , as 'q' is constant
We can say that, C₁ / C₂ = V₂ / V₁
4 : 6 = V₂ : V₁
2 : 3 = V₂ : V₁
So,
V₁ = (3/2) V₂ --------- [1]
We know that, V₁ + V₂ = 20 volts -----------[2]
Now by substituting equation [1] in equation [2] ,
(3/2) V₂ + V₂ = 20
(5/2) V₂ = 20
V₂ = 8 volts
We also know that, V₂ = q/C₂
So,
8 = q / 6
Therefore,
q = 48 microC
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