Physics, asked by gudiyadevi0777, 3 months ago


Find accumulated charges
capacitors in the given circuit.

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Answers

Answered by Vamsi8469
1

Answer:

Va = Vb = 20 Volts

As capacitors are in series connection, the accumulated charges in both the capacitors will be of same value..

From the equation, q = C.V , as 'q' is constant

We can say that, C₁ / C₂ = V₂ / V₁

4 : 6 = V₂ : V₁

2 : 3 = V₂ : V₁

So,

V₁ = (3/2) V₂ --------- [1]

We know that, V₁ + V₂ = 20 volts -----------[2]

Now by substituting equation [1] in equation [2] ,

(3/2) V₂ + V₂ = 20

(5/2) V₂ = 20

V₂ = 8 volts

We also know that, V₂ = q/C₂

So,

8 = q / 6

Therefore,

q = 48 microC

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