Question

Find acute angles A and B, if 2 cos (A + B) = 2 sin (A – B) ​

Answer 1

Angles of ‘A’, ‘B’ and ‘C’ are

GIVEN:

A+B+C = 1/2

To find:

Angles of A,B nd C

Solution:

Let us take the triangle ABC, now as the question says

Therefore, the values can be written, as

and for the cosine the value is

So, as we know that the sum of all ‘sides of a triangle’ is 180,

Hence,

With all the equation, we can find the values of A, B and C. Equating all equation:

Let us take

Substituting value of A+B=C+30 in A+B+C=180, we get

Now with we can find the value of A and B, putting the value of C in A+B=C+30 we get

And putting the value of we get B+75-A=45; B-A=-30 or A-B=30

Equate A-B=30 & A+B=105 we get the value of A as

Therefore, value of B is

Hence, the angles of ‘A’, ‘B’ and ‘C’ are

Answer 2

Answer:

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