Find acute angles A and B. If Sin(A+2B)= root3/2
and Cos(A+4B)=0, A>B
Answers
Answered by
36
Answer:
Sin(A+2B) = Sin 60
Cos(A+4B) = Cos 90
A+2B = 60
A+4B = 90
Subtract both
-2B = -30
B = 15
Substitute in any one equation
A+2(15) = 60
A+ 30 = 60
A = 60-30
A = 30
Step-by-step explanation:
Answered by
4
Answer:
A=30° and B=15°
it may help you......:)
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