find AD if the area of the ABC is 28cm2 and the side BC= 7cm
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Step-by-step explanation:
Given
AD is the median of △ABC and E is the midpoint of AD
Through D
draw DG∥BF
In △ADG
E is the midpoint ofAD and EF∥DG
By converse of midpoint theorem we have
F is midpoint of AG and AF=FG ..............1
Similarly, in △BCF
D is the midpoint of BC and DG∥BF
G is midpoint of CF and FG=GC ..............2
From equations 1 and 2
we will get
AF=FG=GC ........3
AF+FG+GC=AC
AF+AF+AF=AC (from eu 3)
3AF=AC
AF=31AC
∴AF=31×15=5cm
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