find AF, BD and CE if AB=15 CM, AC=13 CM, BC=14 CM
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n ∆ABC, AB = 15 cm , BC = 13 cm and AC = 14 cm.
↪ By Heron's formula ,
↪
= √S (S–A) (S–B) (S–C)
= √21 (21–15) (21–13) (21–14)
= √21 (6) (8) (7)
= √7056
↪
Therefore, the area of ∆ABC is 84cm² and its altitude on AC is 12 cm
Step-by-step explanation:
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