Math, asked by gaurav242, 1 year ago

find Ages of a and b are in the ratio 5:7 eight years ago their ages were in the ratio 7:13 find their present age

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Answered by Anonymous
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Q. Find Ages of A and B are in the ratio 5 : 7, Eight years ago, their ages were in the ratio 7 : 13. Find their present age.

Answer :




Let the present ages of A and B be 5x and 7x years respectively.

A'S age 8 years ago = (5x - 8) years.

B's age 8 years ago = (7x - 8) years.

 \frac{5x - 8}{7x - 8} = \frac{7}{13}  ⇒ 13(5x - 8) = 7(7x - 8)

                                                                              ⇒ 65x - 104 = 49x - 56

                                                                              ⇒ 65x - 49x = 104 - 56

                                                                              ⇒ 16x = 48

                                                                              ⇒ x =  \frac{48}{16} = 3

∴ A's present age = 5x years = ( 5 × 3) years = 15 years.

  B's present age = 7x years = (7 × 3) years = 21 years.

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