Find alfa and beta are the zeros of p(x) = 2x²+3x-5. Find (1÷alfa - 1÷beta)
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given,
2x²+3x-5
2x²+5x-2x-5
x(2x+5) -1(2x+5)
x=1. x=-5/2
→1+2/5
7/5
2x²+3x-5
2x²+5x-2x-5
x(2x+5) -1(2x+5)
x=1. x=-5/2
→1+2/5
7/5
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