find all angles of abc
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Step-by-step explanation:
Given -
- ∠ACD = 110°
- ∠A and ∠B are in the ratio 7:4
To Find -
- All angles of ΔABC
As we know that :-
- The sum of the measures of adjacent angles that form a straight line is equal to 180°
- The sum of interior angles of triangle is equal to 180°
Now,
Let x be the angle
Then,
∠A = 7x and ∠B = 4x
And
∠ACD + ∠ACB = 180°
» 110° + ∠ACB = 180°
» ∠ACB = 180° - 110°
- » ∠ACB = 70°
Now,
In ΔABC
» 7x + 4x + 70° = 180°
» 11x = 180° - 70°
» 11x = 110°
- » x = 10°
Hence,
The angles of ΔABC is
∠A = 7x = 7×10 = 70°
∠B = 4x = 4×10 = 40°
∠C = 70°
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Tricky the star has given .....
n thanks tricky .....
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