Find all cube root of √3+i
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would start by converting the number into trigonometric form:
z=√3−i=2[cos(−π6)+isin(−π/6)]
The cube root of this number can be written as:
z1/3
Now with this in mind I use the formula for the nth power of a complex number in trigonometric form:
zn=rn[cos(nθ)+isin(nθ)]
giving:
z13=213[cos(−π6⋅13)+isin(−π6⋅13)]=213[cos(−π18)+isin(−π18)]
Which in rectangular is:
4.2
−
0.7i
hoi
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