Find all integers n > l such that 1" + 2 +...+(n − 1)" is divisible by n.
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Step-by-step explanation:
n2+1n+1 is a natural number
⇔n2+2n+1−2nn+1 is a natural number
⇔(n+1)2−2nn+1 is a natural number
⇔n+1−2n+2−2n+1 is a natural number
⇔n+1−2−2n+1 is a natural number
⇔(n+1)|2
⇔n=1 because n must be a positive odd number and 2 is divisible by (n+1).
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