Find the value of a and b so that p(x)=x^4-10x^2+ax+b is exactly divisible by (x-1) and (x-2) ???
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x3 - 10x2 +ax +b = f(x)
if f (x) is divisible by (x-1) and(x-2)
= f (1)= 1-10+a+b=0 = a+ b = 9
f(2)=8-40+2a+b=0 = 2a +b=
32
a= 23 b = -14
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