Question

find all natural no. n such that (n+1)^2 is divisible by 7​

Answer 1

Step-by-step explanation:

Let m be the quotient after dividing (n+1)&^2 by 7

>>(n+1)^2/7=m

>(n+1)^2=7m

$(n + 1) = \sqrt{7m} \\ n = \sqrt{7m} + 1 \: where \: m \: is \: a \: real \: number \: \:$