Question

find all pairs of consecoutine odd poritive
integers. Both of which are smaller than
10. Such that their sum is more than 11.​

Answer 1

Step-by-step explanation:

Find all pairs of consecutive odd positive integers both of

which are smaller than 10 such that their sum is more than 11.

Let the smaller odd positive integer be x

Since the larger integer is consecutive odd,

Given,

Both integers are smaller than 10,

i.e. x < 10

&

X + 2 < 10

x < 10-2

X<8

Sum of the two integers is more

than 11.

:x + (x + 2) > 11

2x + 2 > 11

2x > 11 - 2

2x > 9

X> X >- 9 2

X> 4.5