Question

Find all pairs of consecutive Odd positive integers both of which are smaller than 10 such that their sum is more than 11.

Answer 1

Define x:

Let one of the number be x

The other number is x + 2

Solve x :

x + x + 2 > 11

2x > 11

x > 5.5

⇒ The number must be greater than 5.5. The first odd integer greater than 5.5 is 7.

Rules for the possible pairs of integer

1) Integer must be odd

2) Integer must be smaller than 10

3) Smallest number must be greater than 5.5

Find the possible pairs:

1) 7 + 9

Next set of number will be greater than 10, therefore there is only 1 set.

Answer: The only pair is 7 and 9

Answer 2

Answer:

Here the ans. is 5,7,9

Step-by-step explanation:

Let the 1st no. be 'x'

Then another no. be= x+2

Now,

Solving for 'x' :

x+x+2> 11

2x +2> 11

2x > 11-2

2x >9

x > 4.5

Now, here the first odd no. after 4.5 is 5 and so we'll get our ans as

{5,7,9}