Find all possible solutions of the following pair of linear equation : 5x+6y=16 & 2x-2y =2
Answers
Answer:
5x+6y=16(×2)
2x-2y=2(×5)
Using elimation method
10x+12y=32
10x-10y=10
- + -
________
22y=22
y=22
__
22
y=1
Then2x-2(1)=2
2x-2=2
2x=4
x=2
Y=1 / x=2 answer
Answer:
The value of y = 1 and x = 2.
Step-by-step explanation:
Given:
5x + 6y = 16
2x - 2y = 2
To find:
all possible solutions by the pair of linear equations.
Step 1
Let, 5x+6y=16 .....(1)
2x-2y =2 .....(2)
Multiplying (1) by 2, we get
2 (5x+6y = 16) = 10x+12y=32
Multiplying (2) by 5, we get
5 (2x - 2y = 2) = 10x - 10y = 10
Step 2
Using Elimination method
10x + 12y = 32 -
10x - 10y = 10
____________
22y = 22
y = 22/ 22
___________
y = 1
Step 3
Substituting the value of y in (2), we get
2x - 2 (1) = 2
Simplifying the above equation, we get
2x - 2 = 2
2x = 4
x = 2
Therefore, the value of y = 1 and x = 2.
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