Find all possible values of X for which the number 7×3 is divisible by 3
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We know that the given number
18x71
is divisible by 3.
And, if a number is divisible by 3 then sum of digits must be a multiple of 3.
i.e., 1+8+x+7+1= multiple of 3
x+17=0,3,6,9,12,15…
Here x is a digit, where, x can have values between 0 and 9.
x+17=18 which gives x=1.
x+17=21 which gives x=4.
x+17=24 which gives x=7.
Hence, x=1,4,7.
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