Find all real numbers x that satisfy the equation (x-4)(x+3) = 0.
Answers
Answer:
x = 4 or x = -3
Step-by-step explanation:
Let's consider the first form which is (x-4)
So, according to the question, (x-4) = 0
x = 4
Now, let's consider the second form that is (x+3) = 0
x = -3
This is your answer.
Hope it helps!
Answer:
The answer to this question is 4,3,
Step-by-step explanation:
The equation (x-4)(x+3) = 0 states that the product of two factors is equal to zero. For a product to equal zero, one of the factors must equal zero. Therefore, the solution for x are 4 and -3.
So, the real numbers that satisfy the equation (x-4)(x+3) = 0 are x = 4 and x = -3. These are called the roots or zeros of the equation. The x-values 4 and -3 are the points at which the equation intersects the x-axis. To find the zeros, one can set each factor equal to zero and solve for x, or apply the Zero Product Property, which states that if the product of two numbers is equal to zero, then at least one of the numbers must be equal to zero.
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