Math, asked by aaaaaaq, 10 hours ago

Find all solutions of the equation in the interval [0,2pi)
28 sin^2 x = 28-14 cos x

Answers

Answered by 44PurpleOcean

2

Answer:

We need

sin2x = 2sinx cosx

Therefore,

sin2x = cosx

sin2x − cosx =0

2sinx cosx − cosx =0

cosx(2sinx −1) =0

Previous Question

Next Question

Similar questions

Math, 5 hours ago

In the measuring tapes (sewing tape) 5'9'' is marked as 151cm, while conversion gives 5'9'' to be 175cm, why is the difference in length occuring? And which one is accurate?

CBSE BOARD X, 5 hours ago

which protects the spinal cord...

Physics, 5 hours ago

Identify square root of 2 as either rational or irrational, and approximate to the tenths place. Arch Hru!

English, 10 hours ago

Neha Madan (a customer) has to sent an email. Select the most appropriate salutations. 1. Dear Madan, 2. Dear Ms Neha Madan 3. Dear Neha, 4. Dear customer,...

Math, 10 hours ago

m PSQ = _____ 132° 312° 48°...

English, 8 months ago

Fish, sea food meaning...

Biology, 8 months ago

what is harmful viruses...

English, 8 months ago

socioeconomic and political impression of a non international armed conflict with special emphasis on venezuela vs usa I need positive point related to usa...