find all the altitudes of a triangle whose sides are 80 cm,100cm and 22cm
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Area of a triange by heron's formulae
semi perimeter =A+B+C/2
=> (80+100+22)Cm/2
=> 202/2 = 101
Area = √S(s-a)(s-b)(s-c)
=> √101(101-80)(101-100)(101-22)
=> √101*21*1*79
=> 167559
=> 8379 Cm square
Area of triange =1/2*base*hieght
8379cm square =1/2*22*h
8379/11= height.
. .
. Altitude=761.7272727
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