Question

find all the angles of the given cyclic quadrilateral ABCD in the figure ​

Answer 1

Answer:

Step-by-step explanation:

2y+4+4y-4=180  =>  6y=180 => y=30

6x-4+7x+2=180  =>  13x=180 => x=14

A= 2y+4 = 64

B=6x-4 = 80

C=4y-4 = 116

D=7x+2 = 100

Answer 2

Answer:

at first,it is a cyclic quadrilateral.

so,the sum of it's opposite angles are 180.

then,

2y+4+4y-4=180

6y=180

y=30

so,angle A=2*30+4=64

angle C=4*30-4=116

again doing the same step.

7x+2+6x-4=180

13x-2=180

13x=182

X=14

so,angle B =6*14-4=80

and angle D=7*14+2=100