Question

find all the angles (x,y,z) in the given figure
​

Answer 1

Step-by-step explanation:

From the right angled triangle on the right, x^2 + 6^2 = 10^2, or

x^2 + 36 = 100, or

x^2 = 100 - 36 = 64 or 8^2.

Hence x = 8.

From the right angled triangle on the left, the base angles are 30 and 90 degrees, so the vertical angle is 180–30–90=30 degrees.

Sin 30 = 0.5 = x/y. But we got x = 8, so y = 8/0.5 = 16 or y = 16.

In the right angled triangle, sin z = x/10 = 8/10 or 0.8, From trigonometrical tables, sin (inverse) 0.8, so z = 53.13010235 degrees.

Answer 2

Answer:

y=80°(opposite angles are equal)

x+80°=180°(adjacent angles are supplementary)

x=180°-80°

x=100°

let the angle opposite to x be <1

x=<1

100°=<1(opposite angles are equal)

<1+z=180°(linear pair)

100°+z=180°

z=180°-100°

z=80°

Step-by-step explanation:

I HOPE IT WILL HELP TOU