find all the angles (x,y,z) in the given figure
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Step-by-step explanation:
From the right angled triangle on the right, x^2 + 6^2 = 10^2, or
x^2 + 36 = 100, or
x^2 = 100 - 36 = 64 or 8^2.
Hence x = 8.
From the right angled triangle on the left, the base angles are 30 and 90 degrees, so the vertical angle is 180–30–90=30 degrees.
Sin 30 = 0.5 = x/y. But we got x = 8, so y = 8/0.5 = 16 or y = 16.
In the right angled triangle, sin z = x/10 = 8/10 or 0.8, From trigonometrical tables, sin (inverse) 0.8, so z = 53.13010235 degrees.
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Answer:
y=80°(opposite angles are equal)
x+80°=180°(adjacent angles are supplementary)
x=180°-80°
x=100°
let the angle opposite to x be <1
x=<1
100°=<1(opposite angles are equal)
<1+z=180°(linear pair)
100°+z=180°
z=180°-100°
z=80°
Step-by-step explanation:
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