Question

find all the factors of 4L^2 mn (^ symbol represents to the power of L)​

Answer 1

Answer:

Step-by-step explanation:

the factors are= 4,L,L,m and n

Answer 2

Given : 4L²mn

To find: All factors

Solution:

4L²mn

= 2² × L² × m¹  × n¹

Assuming that  

2 , L , m & n are co prime numbers

Then number of Factors

(2 + 1)(2 + 1)(1 + 1)(1 + 1)

= 3 * 3 * 2 * 2

= 36

There  will be 36 Factors

Factors would be

1

2

4

L

m

n

L²

Lm

Ln

mn

Lmn

L²m

L²n

L²mn

2L

2m

2n

2L²

2Lm

2Ln

2mn

2Lmn

2L²m

2L²n

2L²mn

4L

4m

4n

4L²

4Lm

4Ln

4mn

4Lmn

4L²m

4L²n

4L²mn

Learn More:

How many factors of 4^8*6^3*7^2 are perfect squares? - Brainly.in

https://brainly.in/question/9011065

12 is a factor of 36,the second factor​ - Brainly.in

https://brainly.in/question/13201623