Question

Find all the pairs of numbers that have a HCF of 30 and LCM of 3150.​

Answer 1

Answer:

Divide lcm by hcf then factor that and any factorization you get can be put into two numbers that when each multiplied by hcf give you a number in a pair. If b is the other no., then, b=c/a. The product of LCM and HCF of two numbers is 24 times of the smaller number.

Answer 2

Step-by-step explanation:

3150 = 30 * 105

now 30 has been taken out 105 to be taken as product of 2 coprimes or one of them 1)

105 = 3* 35

105 = 7 * 15

105 = 5 * 21

105 = 1 * 106

eah pair is a coprime

so numbers = 30*3 and 30 * 35 = 90 and 1050

30*7 and 30 * 15 = 210 and 450

30 *5 and 30*21 = 150 and 630

these are 3 sets other than 30 and 3150 .

HOPE IT HELPS :)