find all the root of the equation x9-x5+x4-1=0
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Answer:
Give equation, x
9
−x
5
+x
4
+x
2
+1=0, has two changes of signs. Hence there can be a maximum of 2 positive roots.
f(−x)=−x
9
+x
5
+x
4
+x
2
+1=0, which has one changes of signs. Hence the given equation has a maximum of 1 negative roots.
Now, as the equation is of 9
th
degree, it must have at least (9−2−1)=6 imaginary roots.
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