find all the zeroes of 2x degree 4 -3xdegree 3 - 3xdegree degree 2 + 6x - 2, if you know that two of its zeroes are plus - root 2and -root 2
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Answer:
The answer is 1/2 and 1
Step-by-step explanation:
Let us form a new polynomial by √2 and -√2
α+β = √2-√2 = 0 αβ = √2x-√2 = -2
x² - ( α+β )x + αβ
x²-2
Let us divide 2xdegree 4 - 3x³ - 3x² + 6x -2 by x²-2
If we divide we will get quotient as 2x²-3x+1
Let us solve for x.
2x²-2x-x+1
2x(x-1) -1 (x-1)
(2x-1) (x-1)
x= 1/2 x= 1
Thank u
Hare Krsna
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