Find all the zeroes of f(x) = x^3 - 2x.plz tell fast
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Answered by
2
f(x)=x³-2x=0
=>x(x²-2)=0
=>x(x-√2)(x+√2)=0
So, the roots are -√2,√2,0.
Answered by
1
Solutions:
f(x) = x³ - 2x = 0
x(x² - 2) = 0
x(x - √2)(x + √2) = 0
So, the roots are -√2, √2, 0.
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