The pitch of a screw gauge is 1 mm and three are 100 divisions on its circular scale. When nothing is put in between its jaws, the zero of the circular scale lies 6 divisions below the reference line. When a wire a placed between the jaws, 2 linear scale divisions are clearly visible while 62 divisions on circular scale coincide with the reference line. Determine the diameter of the wire.
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LC=pitch/n=1mm/100=0.01mm
the instrument has a positive zero error.
e=+n(LC)=+(6×0.01)=+0.06mm
lincar scale reading = 2 ×(1mm)=2mm
circular scale reading =62×(0.01)mm=6.2mm
measured reading =2+0.62=2.62mm
or true reading =2.62-0.06=2.56mm
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