Question

find all the zeroes of the polynomial p(x) = x4 – 7x³ + 9x² + 13x – 4, if two of its zeroes are 2 + √ 3 and 2 - √ 3.

Answer 1

Answer:

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Step-by-step explanation:

polynomial of the two zeroes

(x - (2+rt(3))(x - (2-rt(3)) = x^2 -4x +1

divide it

(x^4 - 7x^3 + 9x^2 + 13x – 4) / (x^2 -4x +1)

= x^2 - 3x -4

= (x-4)(x+1)

x=-1, 4 ... the remaining zeroes

Answer 2

Answer:

SEE BELOW

Step-by-step explanation:

Other two zeroes are 4 & -1.

Hence all the zeroes of the polynomial p(x) = x⁴-7x³+9x²+13x-4 are 2+√3, 2-√3, 4 & -1.