Find all the zeroes of the polynomial
if its two zeroes are
want even steps please
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Hiii Friend,
-✓3/2 and ✓3/2 are the Zeros of the polynomial 2X⁴-2X³-7X²+3X+6
(X+✓3/2) ( X-✓3/2) = X²-(✓3/✓2)² = X²-3/2 = 2X²-3/2 .
Consequently , (2X²-3) is a factor of P(X)
P(X) = 2X⁴-2X³-7X²+3X+6
G(X) = 2X²-3
On dividing P(X) by G(X) we get,
Reminder = 0
Quotient = X²-X-2
Factories the Quotient then we will get the two other zeros of P(X).
=> X²-X-2
=> X²-2X+X-2
=> X(X-2) +1(X-2)
=> (X-2) (X+1)
=> (X-2) = 0 OR (X+1) = 0
=> X = 2 OR X = -1
Hence,
2 , -1 , ✓3/2 and -✓3/2 are the four zeros of the polynomial 2X⁴-2X³-7X²+3X+6.
HOPE IT WILL HELP YOU...... :-)
-✓3/2 and ✓3/2 are the Zeros of the polynomial 2X⁴-2X³-7X²+3X+6
(X+✓3/2) ( X-✓3/2) = X²-(✓3/✓2)² = X²-3/2 = 2X²-3/2 .
Consequently , (2X²-3) is a factor of P(X)
P(X) = 2X⁴-2X³-7X²+3X+6
G(X) = 2X²-3
On dividing P(X) by G(X) we get,
Reminder = 0
Quotient = X²-X-2
Factories the Quotient then we will get the two other zeros of P(X).
=> X²-X-2
=> X²-2X+X-2
=> X(X-2) +1(X-2)
=> (X-2) (X+1)
=> (X-2) = 0 OR (X+1) = 0
=> X = 2 OR X = -1
Hence,
2 , -1 , ✓3/2 and -✓3/2 are the four zeros of the polynomial 2X⁴-2X³-7X²+3X+6.
HOPE IT WILL HELP YOU...... :-)
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