Question

If

${x}^{2} + \frac{1}{ {x}^{2} } = 27$
Then find
$x + \frac{1}{x}$
Using algebric identities

Answer 1

Solution:-

given:-

${x}^{2} + \frac{1}{ {x}^{2} } = 27 \\ Then find \\ x + \frac{1}{x} \\( {x + \frac{1}{x} )}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } + 2 \\ ( {x + \frac{1}{x} )}^{2} = 27 + 2 \\ (x + \frac{1}{x} ) = \sqrt{29} ans$