find all the zeroes of ( x4 + x3 + 23x2 - 3x + 60) if it is given that two of its zeroes are root3 and -root3
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(x - root3)*(x + root3) is one factor
By using identity
(x^2 - 3) is one factor
x^4 + x^3 - 23x^2 - 3x + 60 / x^2 - 3
= x^2 + x - 20
The zeroes of x^2 + x - 20 are -5 and 4
All the zeroes of the given polynomial are
root3, -root3, -5, 4
By using identity
(x^2 - 3) is one factor
x^4 + x^3 - 23x^2 - 3x + 60 / x^2 - 3
= x^2 + x - 20
The zeroes of x^2 + x - 20 are -5 and 4
All the zeroes of the given polynomial are
root3, -root3, -5, 4
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