Question

find all the zeros of 2 x^4 - 3 x cube minus 3 X square + 6 x minus 2 if two of its zeros are 1 and 1/2​

Answer 1

Answer:

Step-by-step explanation:

x = 2 + root3 and x = 2 - root3

these are the zeros of P(x)

( x - 2 - root3 ) ( x - 2 + root3 )

by using formula we know,

( a - b ) ( a +b ) = a^2 - b^2

so now,

( x - 2 )^2 - ( root3 )^2

x^2+ 4 - 4x - 3=0

x² + 1 - 4x ( a)

When we have to  divide P( x ) by  equation a we will get the zero, that is

x=1, and x=-1/2