find all the zeros of 4x4 -20x3 + 5x - 6 if two of its zeroes are 2 and 3
Answers
Answered by
1
Answer:
1/2,-1/2
Step-by-step explanation:
Dividing 4x⁴-20x³+5x-6by(x-2)(x-3), we get:
- 4x²-1=0
- x²-1/4=0
- x²=1/4
- x=+-1/2
Answered by
5
Since two zeroes are 2 and 3.
∴ (x – 2)(x – 3) is a factor of given polynomial.
⇒ x2 – 5x + 6 is a factor of given polynomial.
Now
∴ 4x4 – 20x3 + 23x2 + 5x – 6
= (x2 – 5x + 6)(4x2 – 1)
= (x – 2)(x – 3)(2x – 1)(2x + 1)
∴ Zeroes of the given polynomial are
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