Question

Find all the zeros of find all the zeros of 2 x 4 - 3 x 3 - 3 x square + 6 x minus 2 if two of its zeros are root 2 and minus root 2 ​

Answer 1

Answer:

$1$, $\frac{1}{2}$, $\sqrt{2}$, $-\sqrt{2}$

Step-by-step explanation:

$2x^4-3x^3-3x^2+6x-2=(x-1)(2x-1)(x^2-2)$

Thus the zeroes are $x=1,\frac{1}{2},\pm\sqrt{2}$.

Answer 2

Answer:

Step-by-step explanation:

g(x)=x^2-4

then divide it