Question

Find all the zeros of polynomial 2×4-9×3+5×2+3×1-1 of it zeros are (2+√3) (2-√3)

Answer 1

Answer:

sorry I can't tell answer why because we are out

Answer 2

Answer:

The polynomial is not correct! Maybe due to scanning mistake by the phone...it doesn't even contain any variable..lol

The zeroes given are:

x=(2+√3)

or x–(2+√3)=0

or (x–2)–√3=0 is a factor of p(x)

and,

x=(2–√3)

(x–2)+√3=0 is another factor of p(x).

so, ((x–2)+√3)×((x–2)+–√3)

=(x–2)²–(√3)²

=x²+4–4x–3

or , g(x) = x²–4x+1 is also one of the factor of p(x)

now, divide p(x), (which is ungiven to us.)

by g(x) to obtain q(x) and r(x)=0

Now, factorise q(x) by either mid term splitting, quadratic formula or completing the square method..and compare its factors with zero. The answers will come to you