Find all the zeros of polynomial f(X) =x³ - 2x
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x^3-2x= 0
X(x^2-2)=0
x^2-2=0
x^2=2
x=+_√2
X=√2 & X= -√2
Answered by
1
Given: x³=2x
To find: all the zeroes of the given equation
1. Taking all the terms on LHS:
- let, x^3 - 2x = 0
2. Taking x common from both the terms:
- x(x^2 - 2) = 0
3. now, either x can be zero, or x^2 -2 can be zero
- x^2 - 2 = 0
solving this equation, we get
- x^2=2
x=0
so, there are 3 zeroes and the zeroes of the given equation are 0, ±√2
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