Find all the zeros of polynomial x³+3x²-2x-6, if two zeros are -/2
and /2....!!!
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Answer: -3
Step-by-step explanation:
Since two zeroes are /2 and -/2
so (x+/2)(x-/2)= (x^2-2)
Dividing-:
x^3+3x^2-2x-6 by x^2-2
we get x+3
x= -3
zeroes of the given polynomial are /2,-/2 and-3
since cubic polynomial have three zeroes, hence verified.
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