Question

find all the zeros of the polynomial 2x³-x²-6x-3, if two of its zeros are -√3 and √ 3​

Answer 1

Answer:

2x³-x²-6x-3

${x}^{2} (2x - 1) - 3(2x - 1) \\ = (2x - 1)( {x}^{2} - 3) )$

So,

$x = - \sqrt{3 } \\ \\ x = + \sqrt{3} \\ x = \frac{1}{2}$