Math, asked by shauryaveer2005, 9 months ago


Find all the
zeros of the polynomial f(x) = (x - 3)(x2 - 9x + 20).
1st ques

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Answered by decentdileep
6

(x - 3)( {x}^{2}  - 9x + 20) \\  {x}^{3}  - 3 {x}^{2} - 9 {x}^{2} + 27x + 20x - 60 \\  {x}^{3} - 12 {x}^{2} + 47x - 60 \\ x( {x}^{2} - 12x + 47 - 60) \\  {x}^{2} - 12x - 13 \\ {x}^{2}  - 13x + 1x - 13 \\x(x - 13)1(x - 13) = 0 \\ x + 1 =0 \:  \:  \:  \:  \:  \: x - 13 = 0 \\ x = 1 \:  \:  \:  \:  \: x = 13

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