find all the zeros of the polynomial x^4 -3x^3 +6x -4, if two of its zeros are root2 and -root2
Answers
Answered by
11
sum of zeroes = 3
√2 -√2 + x + y = 3
x + y = 3
product of zeroes = -4
xy ( -√2)(√2) = -4
xy = 2
x = 2/y
2/y + y= 3
2 + y^2 - 3y = 0
y^2 - y - 2y +2 =0
y( y -1) -2( y-1) = 0
y = 2,1
x = 1,2
SO 2 zeroes are 1,2
√2 -√2 + x + y = 3
x + y = 3
product of zeroes = -4
xy ( -√2)(√2) = -4
xy = 2
x = 2/y
2/y + y= 3
2 + y^2 - 3y = 0
y^2 - y - 2y +2 =0
y( y -1) -2( y-1) = 0
y = 2,1
x = 1,2
SO 2 zeroes are 1,2
tanukahlon2:
Your answer is wrong The correct answer is -3
Similar questions