Question

Find all the zeros of (x4 + x3 – 23x2 – 3x + 60), if it is given that two of its
zeros are 13 and - V3.
(CBSE 2009C]
hef​

Answer 1

Answer:

Step-by-step explanation:

(x - root3)*(x + root3) is one factor

By using identity

(x^2 - 3) is one factor

x^4 + x^3 - 23x^2 - 3x + 60 / x^2 - 3

= x^2 + x - 20

The zeroes of x^2 + x - 20 are -5 and 4

All the zeroes of the given polynomial are

root3, -root3, -5, 4

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