Find all values of x for. (sin5x = cos2x) between 0° to 360°
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sin5x = cos2x
cos(π/2 - 5x) = cos2x
π/2 - 5x = 2πn +_ 2x
taking +ve
π/2 - 5x = 2πn + 2x
π/2 = 2πn + 7x
7x = π/2 - 2πn
x = π/14 - 2πn/7
taking -ve
π/2 - 5x = 2πn - 2x
π/2 -2πn = 3x
x = π/6 - 2πn/3
cos(π/2 - 5x) = cos2x
π/2 - 5x = 2πn +_ 2x
taking +ve
π/2 - 5x = 2πn + 2x
π/2 = 2πn + 7x
7x = π/2 - 2πn
x = π/14 - 2πn/7
taking -ve
π/2 - 5x = 2πn - 2x
π/2 -2πn = 3x
x = π/6 - 2πn/3
BorahPanda:
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