Find all zeroes of p (x) = 3x^3-5x^2-11x-3. if you know that two of its zeroes are -1 and 3 plaza answer
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p(x)=3x^3-5x^2-11x-3
it is a cubic polynomial. it has three zeroes. two of its zeroes are given.
finding the factors by solving for each zero
x=-1
x+1=0
x=3
x-3=0
multiply the factors
(x+1)(x-3)
g(x) = x^2-2x-3 is a factor
now by long division method
divide p(x) by g(x)
division is shown in the attachment
when u divide u will get quotient as
3x+1
∴3x+1=0
x=-1/3
∴the zeroes are -1<3,-1/3
hope this answer was helpful
if u didnt understand pls reply in the comment session
are u a 10th grader?
it is a cubic polynomial. it has three zeroes. two of its zeroes are given.
finding the factors by solving for each zero
x=-1
x+1=0
x=3
x-3=0
multiply the factors
(x+1)(x-3)
g(x) = x^2-2x-3 is a factor
now by long division method
divide p(x) by g(x)
division is shown in the attachment
when u divide u will get quotient as
3x+1
∴3x+1=0
x=-1/3
∴the zeroes are -1<3,-1/3
hope this answer was helpful
if u didnt understand pls reply in the comment session
are u a 10th grader?
Attachments:
Anonymous:
oops! i forgot to add the attachment
ok
i added it
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